Là sao!!!!!???????!!!!!???

mik học lớp 5

Ta có : B=(1/5-1/5)-(3/7-3/7)+(5/9-5/9)-(2/11-2/11)+(7/13-7/13)-9/16

B=-9/16

a: \(=\dfrac{4}{5}\cdot\dfrac{7}{3}\cdot\dfrac{3}{7}\cdot\dfrac{5}{4}+2011=2011+1=2012\)

b: \(=\dfrac{1}{3}\cdot\dfrac{9}{7}\cdot\dfrac{7}{9}=\dfrac{1}{3}\)

`a)4/5:3/7xx3/7:4/5+2011`

`=4/5xx7/3xx3/7xx5/4+2011`

`=(4/5xx5/4)xx(7/3xx3/7)+2011`

`=1xx1+2011`

`=1+2011`

`=2012`

__

`b)1/2xx2/3:7/9xx7/9`

`=1/2xx2/3xx9/7xx7/9`

`=(1/2xx2/3)xx(9/7xx7/9)`

`=1/3xx1`

`=1/3`

\(B=\frac{1}{5}-\frac{3}{7}+\frac{5}{9}-\frac{2}{11}+\frac{7}{13}-\frac{9}{16}-\frac{7}{13}+\frac{2}{11}-\frac{5}{9}+\frac{3}{7}-\frac{1}{5}\)

\(B=\left(\frac{1}{5}-\frac{1}{5}\right)+\left(-\frac{3}{7}+\frac{3}{7}\right)+\left(\frac{5}{9}-\frac{5}{9}\right)+\left(-\frac{2}{11}+\frac{2}{11}\right)+\left(\frac{7}{13}-\frac{7}{13}\right)-\frac{9}{16}\)

\(B=0-\frac{9}{16}\)

\(B=-\frac{9}{16}\)

Mình nhớ bài này mình làm rồi 

câu hỏi này bạn này đăng đi đăng lại nhiều lần hoc24 xóa đi

thiếu chữ có ngay chỗ bạn do bấm máy nhanh wá

\(B=\frac{1}{5}-\frac{3}{7}+\frac{5}{9}-\frac{2}{11}+\frac{7}{13}-\frac{9}{16}-\frac{7}{13}+\frac{2}{11}-\frac{5}{9}+\frac{3}{7}-\frac{1}{5}\) 

\(=\frac{1}{5}-\frac{1}{5}-\frac{3}{7}+\frac{3}{7}+\frac{5}{9}-\frac{5}{9}-\frac{2}{11}+\frac{2}{11}+\frac{7}{13}-\frac{7}{13}-\frac{9}{16}\) 

\(=0+0+0+0+0-\frac{9}{16}\) 

\(=\frac{-9}{16}\)

\(B=\frac{\frac{4}{3}+\frac{4}{5}-\frac{4}{9}}{\frac{7}{3}+\frac{7}{5}-\frac{7}{9}}\)

\(=\frac{4.\left(\frac{1}{3}+\frac{1}{5}-\frac{1}{9}\right)}{7.\left(\frac{1}{3}+\frac{1}{5}-\frac{1}{9}\right)}\)

\(=\frac{4}{7}\)

B= \(\frac{\frac{4}{3}+\frac{4}{5}-\frac{4}{9}}{\frac{7}{3}+\frac{7}{5}-\frac{7}{9}}\)=\(\frac{4.\left(\frac{1}{3}+\frac{1}{5}-\frac{1}{9}\right)}{7.\left(\frac{1}{3}+\frac{1}{5}-\frac{1}{9}\right)}\)= \(\frac{4}{7}\)

\(B=\frac{1}{5}-\frac{3}{7}+\frac{5}{9}-\frac{1}{11}+\frac{7}{13}-\frac{9}{16}-\frac{7}{13}+\frac{2}{11}-\frac{5}{9}+\frac{3}{7}-\frac{1}{5}\)

\(B=\left(\frac{1}{5}-\frac{1}{5}\right)+\left(\frac{3}{7}-\frac{3}{7}\right)+\left(\frac{5}{9}-\frac{5}{9}\right)+\left(\frac{2}{11}-\frac{2}{11}\right)\left(\frac{7}{13}-\frac{7}{13}\right)-\frac{9}{16}\)

\(B=0+0+0+0+0-\frac{9}{16}\)

\(B=-\frac{9}{16}\)

\(B=\frac{1}{5}-\frac{3}{7}+\frac{5}{9}-\frac{2}{11}+\frac{7}{13}-\frac{9}{16}-\frac{7}{13}+\frac{2}{11}-\frac{5}{9}+\frac{3}{7}-\frac{1}{5}\)

\(=\left(\frac{1}{5}-\frac{1}{5}\right)+\left(\frac{3}{7}-\frac{3}{7}\right)+\left(\frac{2}{11}-\frac{2}{11}\right)+\left(\frac{7}{13}-\frac{7}{13}\right)-\frac{9}{16}\)

\(=0+0+0+0-\frac{9}{16}\)

\(=\frac{-9}{16}\)

Vậy \(B=\frac{-9}{16}\)

a: \(\dfrac{3}{5}-\dfrac{7}{4}=\dfrac{12}{20}-\dfrac{35}{20}=\dfrac{-23}{20}\)

b: \(\dfrac{4}{5}:\dfrac{-8}{15}=\dfrac{-4}{5}\cdot\dfrac{15}{8}=\dfrac{-60}{40}=\dfrac{-3}{2}\)

c: \(=7+\dfrac{5}{9}-2-\dfrac{3}{4}-3-\dfrac{5}{9}=2-\dfrac{3}{4}=\dfrac{5}{4}\)

d: \(=\dfrac{-3}{7}\left(\dfrac{4}{19}+\dfrac{15}{19}\right)+\dfrac{5}{7}=\dfrac{2}{7}\)

a) = 3.50793650794

b) = 7.35238095238

tui lười viết lắm nên tui chỉ tính ra kết quả thui